(3x^2+9)/(x^2+5x-7)=3

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Solution for (3x^2+9)/(x^2+5x-7)=3 equation: 



(3x^2+9)/(x^2+5x-7)=3

We move all terms to the left:

(3x^2+9)/(x^2+5x-7)-(3)=0



Domain of the equation: (x^2+5x-7)!=0

We move all terms containing x to the left, all other terms to the right

x^2+5x!=7

x∈R



We multiply all the terms by the denominator


(3x^2+9)-3*(x^2+5x-7)=0

We multiply parentheses

-3x^2+(3x^2+9)-15x+21=0

We get rid of parentheses

-3x^2+3x^2-15x+9+21=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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